x^2+(5.2*10^-4)x-(5.2*10^-5)=0

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Solution for x^2+(5.2*10^-4)x-(5.2*10^-5)=0 equation:



x^2+(5.2*10^-4)x-(5.2*10^-5)=0
We add all the numbers together, and all the variables
x^2+(5.2*10^-4)x-5-5.2E=0
We multiply parentheses
x^2+52x^2-4x-5-5.2E=0
We add all the numbers together, and all the variables
53x^2-4x-19.135065508=0
a = 53; b = -4; c = -19.135065508;
Δ = b2-4ac
Δ = -42-4·53·(-19.135065508)
Δ = 4072.6338877
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-4)-\sqrt{4072.6338877}}{2*53}=\frac{4-\sqrt{4072.6338877}}{106} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-4)+\sqrt{4072.6338877}}{2*53}=\frac{4+\sqrt{4072.6338877}}{106} $

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